2.2 – MATERIAL MODELS Using the information below, choose the correct answer to the closest 3 significant figures. For questions 1 through 5, assume plane stress. For questions 6 through 10, assume plane strain. Name Email 1. Assume plane stress: The principal strain one is 373 µ 587 µ 817 µ 800 µ None of the above None 2. Assume plane stress: The principal strain three is 0 -66.7 µ -360 µ 360 µ None of the above None 3. Assume plane stress: The factor of safety to avoid yielding using maximum shear stress theory is 7.5 2.34 3.41 1.39 None of the above None 4. Assume plane stress: The factor of safety to avoid yielding using maximum octahedral shear stress theory is 2.64 1.59 2.34 1.39 None of the above None 5. Assume plane stress: The critical crack length in Mode I is 0.995 inch 0.470 inch 0.497 inch 0.235 inch None of the above None 6. Assume plane strain: The principal stress three is 2 ksi (T) 10.8 ksi (T) 10.8 ksi (C) 2 ksi (C) None of the above None 7. Assume plane strain The principal strain one is 373 µ 587 µ 817 µ 800 µ None of the above None 8. Assume plain strain: The factor of safety to avoid yielding using maximum shear stress theory is 7.5 2.34 3.41 1.39 None of the above None 9. Assume plane strain: The von-Mises stress is 20.79 ksi 36.81 ksi 22.68 ksi 37.89 ksi None of the above None 10. Assume plane strain: The factor of safety to avoid yielding using maximum octahedral shear stress theory is 1.85 2.65 2.89 1.60 None of the above None Do you have any comments or suggestions? Please send them to author@madhuvable.org Time's up