2.2 – MATERIAL MODELS | Mechanics of Materials

Using the information below, choose the correct answer to the closest 3 significant figures. For questions 1 through 5, assume plane stress. For questions 6 through 10, assume plane strain.

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1. Assume plane stress:
The principal strain one is

373 µ

587 µ

817 µ

800 µ

None of the above

2. Assume plane stress:
The principal strain three is

-66.7 µ

-360 µ

360 µ

None of the above

3. Assume plane stress:
The factor of safety to avoid yielding using maximum shear stress theory is

7.5

2.34

3.41

1.39

None of the above

4. Assume plane stress:
The factor of safety to avoid yielding using maximum octahedral shear stress theory is

2.64

1.59

2.34

1.39

None of the above

5. Assume plane stress:
The critical crack length in Mode I is

0.995 inch

0.470 inch

0.497 inch

0.235 inch

None of the above

6. Assume plane strain:
The principal stress three is

2 ksi (T)

10.8 ksi (T)

10.8 ksi (C)

2 ksi (C)

None of the above

7. Assume plane strain
The principal strain one is

373 µ

587 µ

817 µ

800 µ

None of the above

8. Assume plain strain:
The factor of safety to avoid yielding using maximum shear stress theory is

7.5

2.34

3.41

1.39

None of the above

9. Assume plane strain:
The von-Mises stress is

20.79 ksi

36.81 ksi

22.68 ksi

37.89 ksi

None of the above

10. Assume plane strain:
The factor of safety to avoid yielding using maximum octahedral shear stress theory is

1.85

2.65

2.89

1.60

None of the above

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